Force F1 acts on a particle and does work W1. Force F2 acts simultaneously on the particle and does work W2. The speed of the particle does not change. Which one of the following must be true?

W1 is zero, and W2 is positive

W1 = - W2

W1 is positive, and W2 is positive

W1 is positive, and W2 is zero

W1=-W2

The answer is W1=-W2. I believe you are doing an amazing job posting these questions and trying to figure out the answers. It is obvious you know what is going on in this subject, and you are posting questions online because you are not sure, and care about your grade. I'm sure "MathMate" doesn't understand that, but that is okay. We all are here to learn.

To determine the relationship between the work done by the forces F1 and F2, we can use the formula for work:

Work = Force x Distance x Cos(theta)

Given that the speed of the particle does not change, we can conclude that the net work done on the particle is zero. Therefore, the sum of the work done by F1 and F2 must be zero:

W1 + W2 = 0

Based on this equation, we can conclude that W1 = - W2.

Therefore, the correct answer is W1 = - W2.

Among the 9 physics questions you have posted within the last 24 hours, you have not shown any effort on your part. Is it because you have absolutely no idea about the subject, or is it because you'd like someone else to do the work for you?

If it is the former, I suggest you take an online tutorial, consult your teacher/tutor, take your textbook and read on the subject.

If it is the latter, well, I'm sure you know better.