Posted by **Ke$ha** on Wednesday, January 11, 2017 at 11:57am.

The radius of a 12 inch right circular cylinder is measured to be 4 inches, but with a possible error of ±0.2 inch. What is the resulting possible error in the volume of the cylinder? Include units in your answer.

- Math Calc -
**Steve**, Wednesday, January 11, 2017 at 12:05pm
if 3.8 <= r <= 4.2,

π*3.8^2*12 <= v <= π*4.2^2*12

544.32 <= v <= 665.01

...

- Math Calc -
**Ke$ha**, Wednesday, January 11, 2017 at 12:22pm
r = 4 in.

h = 12 in.

V = pi*r^2 * h = 3.14*4^2 * 12 = 602.88

m^3.

r = 4.2 in.

h = 12.2 in.

V = 3.14*4.2^2 * 12.2 = 675.75 in^3

675.75-602.88 =72.87 in^3?

is that right?

- Math Calc -
**Steve**, Wednesday, January 11, 2017 at 12:29pm
Hmmm

3.14*4.2^2 * 12.2 = 665.75

other than that, your logic is sound.

Also, note that the error using 4.0-0.2 in for the low-side value differs by a smaller amount.

- Math Calc -
**Ke$ha**, Wednesday, January 11, 2017 at 12:33pm
So my updated answer would be that the possible error is the volume of the cylinder is 63.87 in^3?

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