Posted by Someone on Wednesday, January 11, 2017 at 11:15am.
A particle moves along the xaxis with position function s(t) = e^cos(x). How many times in the interval [0, 2π] is the velocity equal to 0?
1< My answer
2
3
More than 3
I don't really get this question will someone please explain it to me?

Calculus  Steve, Wednesday, January 11, 2017 at 11:54am
v(x) = sin(x) e^cos(x)
since e^cos(x) is never zero, how many times in sin(x) = 0 in the interval?
Your answer is correct on the interval (0,2π), but not on [0,2π]

Calculus  Ke$ha, Wednesday, January 11, 2017 at 11:59am
what is the difference between the two?

Calculus  Steve, Wednesday, January 11, 2017 at 12:10pm
v(t) = 0 at 0,π,2π
If you exclude the endpoints of the interval, your answer is correct. But, we are working with the closed interval, including the endpoints. So, there are 3 points where v(t) = 0.
Better review interval notation.
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