Posted by **Someone** on Wednesday, January 11, 2017 at 11:15am.

A particle moves along the x-axis with position function s(t) = e^cos(x). How many times in the interval [0, 2π] is the velocity equal to 0?

1< My answer

2

3

More than 3

I don't really get this question will someone please explain it to me?

- Calculus -
**Steve**, Wednesday, January 11, 2017 at 11:54am
v(x) = -sin(x) e^cos(x)

since e^cos(x) is never zero, how many times in sin(x) = 0 in the interval?

Your answer is correct on the interval (0,2π), but not on [0,2π]

- Calculus -
**Ke$ha**, Wednesday, January 11, 2017 at 11:59am
what is the difference between the two?

- Calculus -
**Steve**, Wednesday, January 11, 2017 at 12:10pm
v(t) = 0 at 0,π,2π

If you exclude the endpoints of the interval, your answer is correct. But, we are working with the closed interval, including the endpoints. So, there are 3 points where v(t) = 0.

Better review interval notation.

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