calculate the specific heat capacity of the materials for which the heat supply, mass, and temperature rises are given below:

i)25200J, 0.3Kg,20K
ii)8000J, 500g, from 20'C to 60'C
iii)9450J, 150g, from 15'C to 45'C

calculate the specific heat capacity of the materials for which the heat supply, mass, and temperature rises are given below:

i)25200J, 0.3Kg,20K
ii)8000J, 500g, from 20'C to 60'C
iii)9450J, 150g, from 15'C to 45'C

calculate the specific heat capacity of the materials

25,200j, 0.3kg, 20k

To calculate the specific heat capacity (c) of a material, we can use the formula:

c = Q / (m * ΔT)

Where:
c = specific heat capacity (in J/kg°C)
Q = heat supply (in J)
m = mass of the material (in kg)
ΔT = change in temperature (in °C)

i) For the first case:
Q = 25200 J
m = 0.3 kg
ΔT = 20 K

Let's convert the change in temperature from Kelvin to Celsius:
ΔT = 20 K = 20 °C

Now, we can calculate the specific heat capacity using the formula:

c = 25200 J / (0.3 kg * 20 °C)
c = 420 J/kg°C

Therefore, the specific heat capacity of the material in the first case is 420 J/kg°C.

ii) For the second case:
Q = 8000 J
m = 500 g = 0.5 kg
ΔT = (60 °C - 20 °C)

Now, we can calculate the specific heat capacity using the formula:

c = 8000 J / (0.5 kg * (60 °C - 20 °C))
c = 8000 J / (0.5 kg * 40 °C)
c = 400 J/kg°C

Therefore, the specific heat capacity of the material in the second case is 400 J/kg°C.

iii) For the third case:
Q = 9450 J
m = 150 g = 0.15 kg
ΔT = (45 °C - 15 °C)

Now, we can calculate the specific heat capacity using the formula:

c = 9450 J / (0.15 kg * (45 °C - 15 °C))
c = 9450 J / (0.15 kg * 30 °C)
c = 630 J/kg°C

Therefore, the specific heat capacity of the material in the third case is 630 J/kg°C.

To calculate the specific heat capacity of a material, you can use the formula:

Specific heat capacity (c) = (Heat supply (Q)) / (mass (m) x temperature change (ΔT))

Let's calculate the specific heat capacity for each of the given scenarios:

i) In this case, the heat supply is 25200 J, the mass is 0.3 kg, and the temperature rises by 20 K.

Using the formula, we can calculate:
Specific heat capacity = 25200 J / (0.3 kg x 20 K)
Specific heat capacity = 420 J/(kg·K)

ii) In this case, the heat supply is 8000 J, the mass is 500 g (which is equivalent to 0.5 kg), and the temperature rises from 20°C to 60°C, which is a change of 40 K.

Using the formula, we can calculate:
Specific heat capacity = 8000 J / (0.5 kg x 40 K)
Specific heat capacity = 400 J/(kg·K)

iii) In this case, the heat supply is 9450 J, the mass is 150 g (0.15 kg), and the temperature rises from 15°C to 45°C, which is a change of 30 K.

Using the formula, we can calculate:
Specific heat capacity = 9450 J / (0.15 kg x 30 K)
Specific heat capacity = 6300 J/(kg·K)

Therefore, the specific heat capacity of the materials for the given scenarios are:
i) 420 J/(kg·K)
ii) 400 J/(kg·K)
iii) 6300 J/(kg·K)