Using a for airtime and w for water time ,which system of linear equations would you use to solve this problem?

A stone falls from the top of a cliff into the ocean .
In the air , it had an average speed of 16m/s .In the water ,it had an average speed of 3m/s before hitting the seabed. The total distance from the top of the cliff to the seabed is 127 meters ,and the stone's entire fall took 12 seconds .
How long did the stone fall in air ,and how long did it fall in the water ?
A) a + w = 127 ; 16a +3w = 12
B) a +w =12 ; 16a +3w = 127
C) a- w = 12 ; 16a - 3w =12

hint: a and w are times, and add to 12.

To solve this problem, we can set up a system of linear equations. Let's define 'a' as the time the stone fell in air and 'w' as the time the stone fell in water.

We know that the total distance from the top of the cliff to the seabed is 127 meters. So, the first equation would be a + w = 127.

Additionally, we are given that the stone's average speed in the air is 16 m/s. From this, we can calculate the distance traveled in the air by multiplying the speed by the time: 16a. Similarly, the stone's average speed in the water is 3 m/s, so the distance traveled in the water is 3w.

Since the total distance is 127 meters, we can write the second equation as 16a + 3w = 127.

The correct system of linear equations would be:
A) a + w = 127; 16a + 3w = 12