calculate the solubility of 10.1g of potassium trioxonitrate v dissolved in 50g of disstilled water at 25 degree celsius

https://sites.prairiesouth.ca/legacy/chemistry/chem30/graphics/4_graphics/sol_curve.jpg

Looks like solubility is 40g per 100 g of water, and in 50 g, then 20g, so yes, the 10.1g of KNO3 will dissove. I guess that is what you are asking, you have dissolved 20.2g/100gwater

Solubility is the amount of solid that dissolves in 100g of water at the given temperature.

10.1 g dissolves in 50 g H2O at 25°C
X g dissolves in 100 g H2O at 25°C

Solve for X.

Xg×50g=10.1×100

Xg=10.1×100÷50=20.2g

To calculate the solubility of potassium trioxonitrate V (also known as potassium nitrate, KNO3) in water at 25 degrees Celsius, you need to refer to a solubility table or use the Solubility Product Constant (Ksp) of the compound.

The solubility of a compound is defined as the amount of solute that can dissolve in a given amount of solvent at a specific temperature. Solubility is typically expressed in grams per 100 grams of solvent or moles per liter of solution.

Here are the steps to calculate the solubility of KNO3 in water at 25 degrees Celsius:

Step 1: Determine the mass of the solute (KNO3) and the mass of the solvent (water). In this case, you have 10.1 grams of KNO3 and 50 grams of water.

Step 2: Calculate the molar mass of KNO3. The molar mass of potassium (K) is 39.1 g/mol, nitrogen (N) is 14.0 g/mol, and oxygen (O) is 16.0 g/mol. Therefore, the molar mass of KNO3 is:

(39.1 g/mol (K) + 14.0 g/mol (N) + (3 * 16.0 g/mol (O)) = 101.1 g/mol

Step 3: Convert the mass of KNO3 to moles. Divide the mass of KNO3 (10.1 g) by its molar mass (101.1 g/mol):

10.1 g / 101.1 g/mol = 0.0999 moles (approximately)

Step 4: Convert the mass of water to moles. Divide the mass of water (50 g) by its molar mass, which is approximately 18.0 g/mol (the molar mass of water):

50 g / 18.0 g/mol = 2.78 moles (approximately)

Step 5: Calculate the solubility in moles per liter (mol/L). Since we know the mass of the solute and solvent in grams, we can assume that the volume of the water remains the same as its mass in milliliters (since 1 g of water ≈ 1 mL at room temperature). Therefore, the volume is 50 mL or 0.050 L (50/1000) since the solute is dissolved in 50g (50 mL) of water:

Solubility = Moles of KNO3 / Volume of water (in liters)
= 0.0999 moles / 0.050 L
= 1.998 mol/L (approximately)

So, the solubility of KNO3 in water at 25 degrees Celsius is approximately 1.998 moles per liter (mol/L).