An empty bottle weighs 20 grams and 60 grams when filled completely with water.What would the bottle weigh when filled completely with mercury.
[pw=1.0gcm^-3,pm=1.6gcm^-3]
pm=1.6gcm^-3
nonsense
V = 40 cm^3
so mass = 20 + 40 * density of Hg which is not 1.6 g/cm^3
84grams
To find the weight of the bottle when filled completely with mercury, we need to calculate the weight of the mercury itself as well as the weight of the bottle.
The difference between the weight of the filled bottle and the weight of the empty bottle is the weight of the liquid, which in this case is water. We can use this information to calculate the weight of the water:
Weight of water = Weight of filled bottle - Weight of empty bottle
Weight of water = 60 grams - 20 grams = 40 grams
Now, to find the weight of the mercury, we can use the density of mercury (pm = 1.6 g/cm^3) and the volume of the bottle. However, we only know the density of mercury in grams per cubic centimeter (g/cm^3), so we need to convert the volume of the bottle to cubic centimeters before we can calculate the weight of the mercury.
Assuming the volume of the empty bottle is the same as the volume of the filled bottle:
Volume of the bottle = Volume of water = Weight of water / Density of water (pw = 1.0 g/cm^3)
Volume of the bottle = 40 grams / 1.0 g/cm^3 = 40 cm^3
Now that we have the volume of the bottle, we can calculate the weight of the mercury:
Weight of mercury = Volume of the bottle * Density of mercury
Weight of mercury = 40 cm^3 * 1.6 g/cm^3 = 64 grams
Finally, to find the weight of the filled bottle, we add the weight of the bottle itself to the weight of the mercury:
Weight of filled bottle = Weight of bottle + Weight of mercury
Weight of filled bottle = 20 grams + 64 grams = 84 grams
Therefore, when the bottle is filled completely with mercury, it would weigh 84 grams.