Completely factor: 3j^3 -51j^2 +210j
Thank you very much.
3j(j^2-17j+70)
= 3j(j-10)(j-7)
To completely factor the expression 3j^3 - 51j^2 + 210j, we can start by factoring out the greatest common factor, which is '3j':
3j(j^2 - 17j + 70)
Next, we need to factorize the quadratic expression within the parentheses, j^2 - 17j + 70. We can find two numbers that multiply to give 70 and add up to give -17. The numbers are -7 and -10.
Therefore, the factored form of the expression is:
3j(j - 7)(j - 10)
So, the completely factored form of 3j^3 - 51j^2 + 210j is 3j(j - 7)(j - 10).