ABCD is a rectangle of area 72 square centimeters. The length of AD is 3 times the length of AE.
BF= 8cm
Find the width of the triangle
so, where are E and F?
The width of the rectangle is 364 cm squared.
To find the width of the rectangle, we need to find the length of AE first. Let's assume the width of the rectangle is "x" cm.
We know that the area of a rectangle is given by the formula: Area = length x width.
Given that the area of the rectangle is 72 square centimeters, we have:
72 = length x width
Since the length of AD is 3 times the length of AE, we can write:
AD = 3 x AE
Now, let's calculate the length of AD:
We know that the area of a rectangle is given by the formula: Area = length x width.
Substituting the given values, we have:
72 = (3 x AE) x x
Simplifying the equation, we get:
72 = 3x²
Dividing both sides by 3, we have:
24 = x²
Taking the square root of both sides, we find:
√24 = x
Simplifying the square root, we get:
x ≈ 4.899
Therefore, the width of the rectangle (or the length of AE) is approximately 4.899 cm.