Posted by **lobna** on Friday, January 6, 2017 at 12:44pm.

An investment of $54,000 was made by a business club.The investment was split into three parts and lasted for one year.The first part of the investment earned 8% interest, the second 6%, and the third 9%. Total interest from the investments was $ 4260. The interest from the first investment was 6 times the interest from the second. Find the amounts of the three parts of the investment.

x * 0.08 y* 0.09 z* 0.06 = 4260 I multiply by 100 (1)

8x+9y+6z=426,000 (1)

8x+6(9y)=0 (2)

8x+54y=0 (2)

x+y+z=54,000 (3)

.............................

8x+9y+6z=426,000 (1)

x+y+z=54,000 (3) *-6

-6x-6y-6z=-324000 (4)

........................................

8x+9y+6z=426,000 (1)

-6x-6y-6z=-324000 (4)

..................................

2x+3y=102000 (5) *-4

-8x-12y=-408000

8x+54y=0 (2)

...................................

42y=-408000

y= -68000/7 I find the y

.............................

is that correct ?

- Algebra -
**Steve**, Friday, January 6, 2017 at 7:54pm
how can y be negative?

x+y+z = 54000

.08x + .06y + .09z = 4260

.08x = 6*.06y

x,y,z = 36000, 8000, 10000

-----------------------------------

So, where did you go wrong?

8x+6(9y)=0

Why do you think the interest sums to zero?

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