Water is falling on turbine at a rate of 6000 kg/min the height of fall is 100 m what is the power given to turbine?

100 kg/s

energy (work) = m * g * h
... = 100 kg * 9.8 m/s^2 * 100 m
... = Joules

energy / time = power
... Joule / s = watt

98000watt

To find the power given to the turbine, you need to calculate the potential energy of the falling water and convert it to power. The formula to calculate potential energy is:

Potential Energy (PE) = mass (m) x gravity (g) x height (h)

First, let's convert the rate of water from kg/min to kg/s:
6000 kg/min = 6000 kg/60 s = 100 kg/s

Now, we can calculate the potential energy:
PE = mass (m) x gravity (g) x height (h)
PE = 100 kg/s x 9.8 m/s^2 x 100 m
PE = 98000 J/s

Since power is defined as the rate at which work is done or energy is transferred, we can equate potential energy to power:
Power = Potential Energy / time

So, the power given to the turbine would be 98000 J/s, which is also 98000 watts (W) or 98 kilowatts (kW).