6.0g of cobolt (II) carbonate was added to 40cm3 of hydrochloric acid, concentration 2.0 mol/dm3. Calculate the maximum yield of cobalt (II) choloride-6-water and show that cobalt (II) carbonate was in excess.
CoCO3 +2HCl = CoCl2 +CO2 + H2O
CoCl2 + 6H2O = CoCl2.6H2O
what is the number of HCL moles used?
Well, let's calculate the number of moles of hydrochloric acid used. We can use the formula:
Number of moles = Concentration (mol/dm^3) x Volume (dm^3)
Given that the concentration of hydrochloric acid is 2.0 mol/dm^3 and the volume is 40 cm^3, we need to convert the volume to dm^3:
40 cm^3 = 40/1000 dm^3 = 0.04 dm^3
Now we can calculate the number of moles:
Number of moles = 2.0 mol/dm^3 x 0.04 dm^3 = 0.08 mol
So, the number of moles of hydrochloric acid used is 0.08 mol.
To calculate the number of hydrochloric acid (HCl) moles used, we need to use the formula:
moles = concentration x volume
Given:
Concentration of HCl = 2.0 mol/dm^3
Volume of HCl = 40 cm^3
First, we need to convert the volume from cm^3 to dm^3:
Volume of HCl = 40 cm^3 = 40/1000 dm^3 = 0.04 dm^3
Now we can calculate the number of moles of HCl used:
moles HCl = concentration x volume
= 2.0 mol/dm^3 x 0.04 dm^3
= 0.08 mol
Therefore, the number of HCl moles used is 0.08 mol.
To find the number of moles of hydrochloric acid (HCl) used, we need to use the given information about the concentration and volume.
Given:
Concentration of HCl = 2.0 mol/dm3
Volume of HCl = 40 cm3
First, let's convert the volume from cm3 to dm3:
1 dm3 = 1000 cm3
40 cm3 = 40/1000 dm3 = 0.04 dm3
Now we can calculate the number of moles of HCl used:
Number of moles of HCl = Concentration of HCl x Volume of HCl
= 2.0 mol/dm3 x 0.04 dm3
= 0.08 moles
Therefore, the number of moles of hydrochloric acid (HCl) used is 0.08 moles.
1. Calculate moles of CoCO3
=6.0/(58.933+12.0+3*16.0)
=6.0/118.9
=0.0504 mol
2. Calculate moles of HCl
=40/1000*2.0 mol
=0.080
Using stoiciometric ratios
CoCO3 used = 0.08*1/2=0.04 mols
=> CoCO3 is in excess (<0.0504).
The remaining answer can be obtained by finding the mass of 0.040 mol of CoCl2 and H2O respectively.
[assuming choloride-6-water meant
choloride-&-water]