Hello,
Which one is correct?
1) NaOH(aq) + HNO3(aq) ⇋ NaNO3(aq) + H2O(l)
or
2) NaNO3(s) + H2O(l) ⇋ NaOH(aq) + HNO3(aq)
Thanks!!
The first one. Soduum nitrate is soluble in water.
Is this correct though?
NaNO3(s) + H2O(l) = NaOH(aq) + HNO3(aq)
To determine which equation is correct, we need to consider the solubility of the compounds involved.
The reaction you are asking about involves sodium hydroxide (NaOH), nitric acid (HNO3), sodium nitrate (NaNO3), and water (H2O).
In the first equation:
NaOH(aq) + HNO3(aq) ⇋ NaNO3(aq) + H2O(l)
In the second equation:
NaNO3(s) + H2O(l) ⇋ NaOH(aq) + HNO3(aq)
To determine the correct equation, we need to determine the solubility of the compounds. Sodium hydroxide (NaOH) and nitric acid (HNO3) are both strong electrolytes and highly soluble in water, so they exist as ions when dissolved in water. Sodium nitrate (NaNO3) is also a strong electrolyte and highly soluble in water.
Based on this information, we can conclude that the correct equation is the first one:
NaOH(aq) + HNO3(aq) ⇋ NaNO3(aq) + H2O(l)
This equation represents the reaction between sodium hydroxide and nitric acid to form sodium nitrate and water, which are all in their dissolved or aqueous state.