Calculate the pressure due to water experienced by a diver working 25m below the surface of water in dam.(density of water is 1g/cm3 and g=10N/kg.
density = 1000 kg/m^3 is easier :)
You do not say if you want gage pressure or absolute pressure
I will assume gage
rho g h = 1000*10*25 =2.5 *10^5 Pascals or N/m^2
if you want absolute pressure add one atmophere or about 1*10^5 for a total of 3.5*10^5 Pascals
To calculate the pressure due to water, you can use the formula:
P = ρ * g * h
where P is the pressure, ρ is the density of water, g is the acceleration due to gravity, and h is the depth.
Given:
ρ (density of water) = 1 g/cm³
g (acceleration due to gravity) = 10 N/kg
h (depth) = 25 m
First, let's convert the density of water from g/cm³ to kg/m³:
1 g/cm³ = 1000 kg/m³
So, ρ = 1000 kg/m³
Now we can substitute the given values into the formula to calculate the pressure:
P = (1000 kg/m³) * (10 N/kg) * (25 m)
P = 250,000 N/m²
Therefore, the pressure due to water experienced by the diver is 250,000 N/m² or 250 kPa (kilopascals).