A given volume of ozone diffused from a certain apparatus in 96seconds calculate the time taken by an equal volume of carbonoxide to diffuse under the same condition?
R1/R2=sqrt(MW2/MW1)
But we are given the inverses of rates, (times), so
T2/T1=sqrt(MW2/MW1)
ozone MW1=16*3=48
CO MW2=28
T1=96seconds
T2 (CO)=96*sqrt(28/48) seconds
Well, let's see. Ozone and carbon monoxide are quite different gases. So, while ozone might be quick to diffuse, carbon monoxide might be a bit more sluggish. In fact, carbon monoxide can be quite the sneaky gas!
I'm not sure about specific numbers, but I can tell you this: if it takes ozone 96 seconds to diffuse, you can probably bet that carbon monoxide is taking its time, enjoying the scenic route, and maybe even stopping for a coffee along the way. So, my guess is that the time taken by an equal volume of carbon monoxide to diffuse under the same conditions would be longer than 96 seconds.
But hey, don't take my word for it. Maybe carbon monoxide has a secret jetpack that I don't know about. Anything's possible in the world of science!
To calculate the time taken by an equal volume of carbon monoxide (CO) to diffuse under the same conditions, we need to use Graham's Law of Diffusion.
Graham's Law states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.
Mathematically, we can express this as:
Rate1 / Rate2 = sqrt(molar mass2 / molar mass1)
In this case, we are given that the volume of ozone (O3) diffused in 96 seconds. However, we don't have the molar mass of either gas. So, we cannot calculate the exact time.
To calculate the time, we need the molar masses of ozone (O3) and carbon monoxide (CO). Once we have those values, we can plug them into the formula above to determine the ratio of diffusion rates.
Please provide the molar masses of ozone (O3) and carbon monoxide (CO) so that we can continue the calculations.
To determine the time taken by an equal volume of carbon monoxide (CO) to diffuse under the same conditions, we can use Graham's Law of Diffusion. Graham's Law states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.
Here are the steps to find the time taken by CO to diffuse:
1. Determine the molar mass of ozone (O3) and carbon monoxide (CO). The molar mass of O3 is approximately 48 g/mol, and the molar mass of CO is approximately 28 g/mol.
2. Calculate the square root of the molar masses for both gases. The square root of 48 g/mol is approximately 6.93, and the square root of 28 g/mol is approximately 5.29.
3. Set up a ratio using the square roots of the molar masses. The ratio should be the square root of the molar mass of CO divided by the square root of the molar mass of ozone: 5.29/6.93.
4. Calculate the inverse of the ratio by flipping the numerator and denominator: 6.93/5.29.
5. Multiply the given time for ozone diffusion (96 seconds) by the inverse ratio: 96 * (6.93/5.29).
6. Calculate the time taken by an equal volume of carbon monoxide to diffuse by dividing the above result by 2: (96 * (6.93/5.29)) / 2.
By following these steps, you can find the time taken by an equal volume of carbon monoxide to diffuse under the same conditions.