Sodium (Na) reacts with chlorine gas (Cl2) to form sodium chloride (NaCl) as shown in the equation
2Na+Cl2=2nacl
If 4 moles of sodium react, how many moles of chlorine gas will react?
I have no idea what to do.......... I need some assistance thanks
the equation says that 2 moles of Na react with 1 mole of Cl2
4/2 = 2, so just multiply all the quantities by 2:
4 moles Na react with 2 moles Cl2.
Sodium burns vigorously with Golden yellow flame
To determine the number of moles of chlorine gas that will react with 4 moles of sodium, you can use the mole ratio from the balanced chemical equation.
The balanced equation states that 2 moles of sodium react with 1 mole of chlorine gas to form 2 moles of sodium chloride. This can be represented as:
2Na + Cl2 → 2NaCl
From this equation, we can see that the mole ratio between sodium and chlorine gas is 2:1. This means that for every 2 moles of sodium, we need 1 mole of chlorine gas.
Given that we have 4 moles of sodium, we can use the mole ratio to calculate the number of moles of chlorine gas required.
4 moles Na × (1 mole Cl2 / 2 moles Na) = 2 moles Cl2
Therefore, 4 moles of sodium will react with 2 moles of chlorine gas.
No problem! To determine the number of moles of chlorine gas that will react when 4 moles of sodium react, we can use the stoichiometry of the balanced chemical equation you provided.
The equation tells us that 2 moles of sodium react with 1 mole of chlorine gas to produce 2 moles of sodium chloride. Therefore, the mole ratio of sodium to chlorine gas is 2:1.
Since we have 4 moles of sodium, we can determine the number of moles of chlorine gas by setting up a proportion:
(4 moles of sodium) / (2 moles of sodium chloride) = (x moles of chlorine gas) / (1 mole of sodium chloride)
Cross-multiplying, we have:
4 moles of sodium = 2x moles of chlorine gas
To solve for x, divide both sides of the equation by 2:
2 moles of sodium = x moles of chlorine gas
Therefore, when 4 moles of sodium react, 2 moles of chlorine gas will react.