A line has a slope -4/3 and passes through the point (12,6). Determine three additional points of this line.
I don't know how to do find this
1. get familiar with finding the equation of the line using the Point-Slope form:
(y-y0)=m(x-x0)
m=-4/3
(x0,y0)=(12,6)
Line L : (y-6)=-4/3(x-12)
Simplify
y=-4x/3 + 16+6
or
y=-4x/3+22
To find other points on the line, substitute 3 different values of x and evaluate the corresponding value of y. For example, x=3
y=-4(3)/3+22=-4+22=18
so one of the points is (3,18).