A sample of 76 g of NaCl is dissolved to make 1 L of solution. What is the morality of the solution?
How do I get started solving this problem?
Is this a sarcastic comment, Ms. Sue? Kinda weird to find you joking here.
I didn't know that solutions had morality. I wish everyone had morality.
morality ≠ molarity lol
molarity is the fraction
mass of substance contained in 1 L of solution ÷ molecular mass of the substance.
Note:
atomic mass of Na ~ 23
atomic mass of Cl ~ 35.5
so molecular mass of NaCl ~ 58.5
But you need to look up exact masses from periodic tables, and the answer should be accurate two significant digits (because the sample's 76 g has 2 significant digits only).
Thank you MathMate for your time to help me :) So is the equation going to start off as 1 L / 76 g ?
No.
M = mols/L
mols = grams/molar mass
Substitute and solve for M.
To determine the molarity of the solution, you need to know the number of moles of NaCl present in 1 liter of the solution. Here's how you can get started:
1. Begin by calculating the number of moles of NaCl in the sample.
- The molar mass of NaCl is approximately 58.44 g/mol (22.99 g/mol for Na + 35.45 g/mol for Cl).
- Divide the mass of NaCl (76 g) by its molar mass to find the number of moles.
Moles of NaCl = Mass of NaCl / Molar mass of NaCl
2. Now, determine the molarity of the solution.
- To find the molarity, divide the number of moles of NaCl by the volume of the solution in liters.
Molarity (M) = Moles of solute / Volume of solution (in liters)
In this case, the volume of the solution is given as 1 L.
By following these steps, you should be able to determine the molarity of the solution.