If 120. g of propane, C3H8, is burned in excess oxygen according to the following equation: C3H8 + 5O2 3CO2 + 4H2O, how many grams of water are formed?
196.36g
Molecular mass of propane (C3H8)
= 3*12+8*1
= 44
Molecular mass of water (H2O)
= 2*1+1*16
= 18
using the balanced equation, we find that the ratio
mass of propane : mass of water
= 1*44 : 4 * 18
= 44 : 72
Hence the mass of water can be calculated.
Note: replace the above approximate atomic masses by the exact values and repeat above calculations.
Well, let's do some math and find out! According to the equation, for every 1 mole of propane, we get 4 moles of water. Since we're given 120 g of propane, we need to figure out how many moles that is.
To do this, we can use the molar mass of propane, which is 44 g/mol. So, 120 g divided by 44 g/mol gives us approximately 2.73 moles of propane.
Now, we know that for every 1 mole of propane, we get 4 moles of water. So, for 2.73 moles of propane, we would get 2.73 times 4 moles of water.
That gives us a total of 10.92 moles of water. And since the molar mass of water is approximately 18 g/mol, we can multiply the number of moles by the molar mass to find the grams of water formed.
So, 10.92 moles times 18 g/mol gives us approximately 196.56 g of water.
Therefore, approximately 196.56 grams of water are formed.
To determine the amount of water formed, we first need to find the moles of propane present. Then, using the stoichiometry of the chemical equation, we can calculate the moles of water formed. Finally, multiplying the moles of water by its molar mass will give us the grams of water formed.
Step 1: Calculate the moles of propane
To find the moles, we can use the molar mass of propane (C3H8). The molar mass of carbon (C) is 12.01 g/mol, while the molar mass of hydrogen (H) is 1.01 g/mol.
Molar mass of C3H8 = (3 * molar mass of C) + (8 * molar mass of H)
Molar mass of C3H8 = (3 * 12.01 g/mol) + (8 * 1.01 g/mol)
Molar mass of C3H8 = 44.11 g/mol
Now, we can calculate the moles of propane using the given mass (120 g) and its molar mass.
Moles of propane = (Mass of propane) / (Molar mass of C3H8)
Moles of propane = 120 g / 44.11 g/mol
Moles of propane ≈ 2.72 mol
Step 2: Use the stoichiometry of the equation to calculate moles of water formed
From the balanced equation, we can see that the coefficient of water (H2O) is 4, which means that for every 4 moles of propane burned, 4 moles of water are formed.
Moles of water formed = (Moles of propane) * (Moles of water / Moles of propane)
Moles of water formed = 2.72 mol * (4 mol water / 4 mol propane)
Moles of water formed = 2.72 mol
Step 3: Convert moles of water to grams of water
To convert moles of water to grams, we need to multiply the moles of water by its molar mass. The molar mass of water (H2O) is 18.02 g/mol.
Grams of water formed = (Moles of water formed) * (Molar mass of H2O)
Grams of water formed = 2.72 mol * 18.02 g/mol
Grams of water formed ≈ 49.14 g
Therefore, approximately 49.14 grams of water are formed when 120 grams of propane are burned.
To calculate how many grams of water are formed when 120 g of propane (C3H8) is burned, you need to use the stoichiometry of the balanced chemical equation.
According to the balanced equation: C3H8 + 5O2 → 3CO2 + 4H2O
From the equation, you can see that every 1 mole of propane (C3H8) produces 4 moles of water (H2O).
Step 1: Convert grams of propane to moles
To do this, you need to know the molar mass of propane (C3H8).
The molar mass of C3H8 = (3 * atomic mass of C) + (8 * atomic mass of H)
Step 2: Use the molar ratio from the balanced equation
From the equation, you know that 1 mole of propane (C3H8) produces 4 moles of water (H2O).
Step 3: Convert moles of water to grams
To convert moles of water to grams, you need to use the molar mass of water (H2O).
Let's calculate now:
Step 1: Calculate the moles of propane.
Molar mass of C = 12.01 g/mol
Molar mass of H = 1.01 g/mol
Molar mass of propane (C3H8) = (3 * 12.01 g/mol) + (8 * 1.01 g/mol)
Now, use the formula:
Moles of propane = Mass of propane / Molar mass of propane
Moles of propane = 120 g / (3 * 12.01 g/mol + 8 * 1.01 g/mol)
Step 2: Calculate the moles of water.
From the balanced equation, you know that every 1 mole of propane produces 4 moles of water.
Moles of water = Moles of propane * (4 moles of water / 1 mole of propane)
Step 3: Convert moles of water to grams.
Molar mass of water (H2O) = (2 * atomic mass of H) + atomic mass of O
Now, use the formula:
Mass of water = Moles of water * Molar mass of water
Mass of water = Moles of water * (2 * 1.01 g/mol + 16.00 g/mol)
Now, input the values and calculate the mass of water formed.