The gas in a cylinder has a volume of 3 liters at a pressure of 106 kPa. The pressure of the gas is increased to 208 kPa. Assuming the temperature remains constant, what would the new volume be? = ....L?
PV=kT
if T is constant, PV is constant. So, you want
208V = 106*3
5.8867....??? is this the answer
or 1.5288...??
To solve this problem, we can use Boyle's Law, which states that for a fixed amount of gas at a constant temperature, the product of its pressure and volume is constant. Mathematically, it can be represented as:
P1 * V1 = P2 * V2
Where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
In this case, we are given the initial volume (V1 = 3 liters) and initial pressure (P1 = 106 kPa). We are also given the final pressure (P2 = 208 kPa) and want to find the final volume (V2).
Using the formula, we can rearrange it to solve for V2:
V2 = (P1 * V1) / P2
Plugging in the given values, we have:
V2 = (106 kPa * 3 liters) / 208 kPa
Now, let's calculate it:
V2 = (318 liters * kPa) / 208 kPa
V2 = 1.53 liters (rounded to two decimal places)
Therefore, the new volume of the gas would be approximately 1.53 liters.