4/9 b^6 writes as a square of a monomial

is it (4/9 b^6)/2

(4b^6)/9 = [(2b^3)/3]^2

To express 4/9 b^6 as a square of a monomial, we need to find a monomial expression that when squared will result in 4/9 b^6.

The square root of 4/9 is 2/3. The square root of b^6 is b^3.

Therefore, (4/9 b^6) can be written as (2/3 b^3)^2.

To write the expression (4/9) * b^6 as a square of a monomial, we need to find a monomial (a term with a coefficient and a variable raised to some power) that, when squared, results in the given expression.

First, let's consider the coefficient, which is 4/9. To square it, we can simply multiply it by itself:
(4/9)^2 = (4/9) * (4/9) = 16/81

Now, let's look at the variable term, which is b^6. To square b^6, we multiply it by itself:
(b^6)^2 = b^(6 * 2) = b^12

Putting it together, the square of the monomial that represents (4/9) * b^6 is:
(16/81) * b^12

Therefore, (4/9) * b^6 does not write as a square of a monomial in the form (4/9 b^6)/2. Instead, it can be written as (16/81) * b^12.

4/9 b^6 = (2/3 b^3)^2