Suppose Set B contains 69 elements and the total number elements in either Set A or Set B is 107. If the Sets A and B have 13 elements in common, how many elements are contained in set A?
A+69-13 = 107
To find the number of elements in Set A, we need to subtract the number of elements in common between Set A and Set B from the total number of elements in both sets (Set A and Set B).
The total number of elements in either Set A or Set B is given as 107, and the number of elements in common between Set A and Set B is 13.
Let's denote the number of elements in Set A as x.
We know that the total number of elements in either Set A or Set B is the sum of the number of elements in Set A, the number of elements in Set B, minus the number of elements in common between them:
x + 69 - 13 = 107
Simplifying the equation:
x + 56 = 107
To isolate x, we subtract 56 from both sides:
x = 107 - 56
x = 51
Therefore, Set A contains 51 elements.