what is the specific heat of aluminum if temperature of a 28.4g sample of aluminum is increased by 8.1 c° when 207J og heat is added
To find the specific heat of aluminum, we can use the equation:
q = m * c * ΔT
Where:
q is the heat transferred (in Joules)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in J/g°C)
ΔT is the change in temperature (in °C)
We're given:
q = 207 J
m = 28.4 g
ΔT = 8.1°C
Now we can rearrange the equation to solve for c:
c = q / (m * ΔT)
Substituting the given values:
c = 207 J / (28.4 g * 8.1°C)
Calculating the value:
c = 0.912 J/(g·°C) (rounded to three decimal places)
Therefore, the specific heat capacity of aluminum is approximately 0.912 J/(g·°C).