3/4 of a number exceeds it's 1/3 by 15. Find the number
36
given the murky question, 36 seems as good an answer as any...
To find the number, let's assign a variable to it. Let's say the number is represented by the variable "x".
According to the problem, 3/4 of the number exceeds its 1/3 by 15.
Mathematically, this can be represented as:
(3/4) * x = (1/3) * x + 15
To solve for x, we'll start by simplifying the equation:
3/4 * x = 1/3 * x + 15
Now, let's eliminate the fractions by multiplying both sides of the equation by a common multiple of the denominators. In this case, the common multiple of 4 and 3 is 12:
12 * (3/4 * x) = 12 * (1/3 * x) + 12 * 15
9x = 4x + 180
Next, we'll move the terms involving x to one side of the equation:
9x - 4x = 180
5x = 180
Finally, to solve for x, we'll divide both sides of the equation by 5:
x = 180 / 5
x = 36
Therefore, the number is 36.