I have 3 1-6 cubes looking for different ways to roll the sum of 12, How many ways will it be?

IDK XD

25 ways

Actually, there are only 3 ways to roll the sum of 12 with 3 1-6 cubes:

1. Roll a 6, a 5, and a 1
2. Roll a 6, a 4, and a 2
3. Roll a 5, a 5, and a 2

So the answer is 3.

3

Yes, that's correct! There are 3 ways to roll the sum of 12 with 3 1-6 cubes.

To determine the different ways to roll the sum of 12 using three 1-6 cubes, we need to consider all the possible combinations.

One approach to solving this is by drawing a table or creating a tree diagram to visualize all the possible outcomes. However, with only three dice and a limited number of outcomes, we can manually list all the possibilities.

First, let's consider the maximum sum we can roll with three 6-sided dice. With each die having a maximum value of 6, the highest sum we can achieve is 6+6+6 = 18.

Now, let's list all the different ways we can roll a sum of 12:

1. Rolling a 6 on one die, a 5 on another, and a 1 on the third: (6, 5, 1)
2. Rolling a 6 on one die, a 4 on another, and a 2 on the third: (6, 4, 2)
3. Rolling a 6 on one die, a 3 on another, and a 3 on the third: (6, 3, 3)
4. Rolling a 5 on one die, a 6 on another, and a 1 on the third: (5, 6, 1)
5. Rolling a 5 on one die, a 5 on another, and a 2 on the third: (5, 5, 2)
6. Rolling a 5 on one die, a 4 on another, and a 3 on the third: (5, 4, 3)
7. Rolling a 4 on one die, a 6 on another, and a 2 on the third: (4, 6, 2)
8. Rolling a 4 on one die, a 5 on another, and a 3 on the third: (4, 5, 3)
9. Rolling a 4 on one die, a 4 on another, and a 4 on the third: (4, 4, 4)
10. Rolling a 3 on one die, a 6 on another, and a 3 on the third: (3, 6, 3)
11. Rolling a 3 on one die, a 5 on another, and a 4 on the third: (3, 5, 4)
12. Rolling a 2 on one die, a 6 on another, and a 4 on the third: (2, 6, 4)

Hence, there are 12 different ways to roll the sum of 12 with three 1-6 cubes.

3C2 = 3