When iron metal reacts with oxygen, the reaction can form Fe2O3. Write a balanced chemical equation for this reaction, and find the number of moles of oxygen that are needed to form 6 mol of Fe2O3.
My answer: 9 moles of oxygen
9 mols O2 is correct; I don't see a balanced equation.
My equation was 4Fe+3O2->2Fe2O3
To write a balanced chemical equation for the reaction between iron metal (Fe) and oxygen (O2) that forms Fe2O3, we need to ensure that the number of atoms of each element is the same on both sides of the equation. The reaction can be represented as follows:
4 Fe + 3 O2 → 2 Fe2O3
To find the number of moles of oxygen needed to form 6 mol of Fe2O3, we can use the stoichiometric coefficients in the balanced equation. In this case, the coefficient of O2 is 3.
According to the stoichiometry, there are 3 moles of O2 required to form 2 moles of Fe2O3. Therefore, to find the number of moles of O2 required for 6 mol of Fe2O3, we can set up a proportion:
(3 mol O2) / (2 mol Fe2O3) = x mol O2 / (6 mol Fe2O3)
Cross-multiplying, we get:
3 mol O2 * 6 mol Fe2O3 = 2 mol Fe2O3 * x mol O2
18 mol O2 = 2x mol O2
Simplifying the equation, we find:
x mol O2 = 18 mol O2 / 2 = 9 mol O2
Therefore, 9 moles of oxygen are needed to form 6 moles of Fe2O3.