Calculate the molarity of 500 ml of a solution containing 100 grams of glucose (C6H12O6).

molarity=moles of solute/liters of solution

1 mol C6H12O6 = 180.15 g

so 100 g/180.15 g = 0.5551 mol C6H12O6

and 1 L = 1000 mL

also 500 mL of soln = 0.500 L

just plug it in

To calculate the molarity of a solution, we need to first determine the number of moles of solute present in the given solution.

To find the number of moles of glucose (C6H12O6), you can use the equation:

moles = mass / molar mass

The molar mass of glucose (C6H12O6) can be calculated by adding up the atomic masses of all the constituent elements:

C: 6 x atomic mass of carbon
H: 12 x atomic mass of hydrogen
O: 6 x atomic mass of oxygen

The atomic masses of carbon, hydrogen, and oxygen can be found on the periodic table or through a quick search.

Once you have the molar mass, substitute it along with the given mass of glucose into the equation to calculate the moles of glucose.

After obtaining the number of moles of glucose, you can then calculate the molarity of the solution using the formula:

Molarity (M) = moles / volume (in liters)

Make sure to convert the volume from milliliters to liters by dividing by 1000.

Let's calculate the molarity step by step.