2. Tell whether the system has one solution infinitely many solutions or no solution.
x=-7y+34
x+7y=32
a. one solution
b. infinitely many solutions
c. no solution***
can you please solve this thank you
Surely you can follow the method I just showed you in your previous question almost identical to this one.
Did you even look at my answer ?
yes i did
I just need to see one more expose so I can understand thoroughly
rearrange the equations. You have
x+7y=34
x+7y=32
Surely it is clear that there is no common solution.
To determine whether the system of equations has one solution, infinitely many solutions, or no solution, we can solve the equations by using the process of elimination.
Given the system of equations:
1) x = -7y + 34
2) x + 7y = 32
We can first rearrange equation 1 to solve for x:
x = -7y + 34
Now substitute this value of x into equation 2:
(-7y + 34) + 7y = 32
Simplify and solve for y:
-7y + 34 + 7y = 32
34 = 32
We see that 34 does not equal 32. This implies that the statement is contradictory, which means there is no solution.
Therefore, the correct answer is c. no solution.