A SOFTBALL DIAMOND IS A SQUARE WITH SIDES OF 60 FT LONG. HOW FAR IS THIRD TO FIRST BASE. ROUND TO THE NEAREST HUNDRETH.
SO FROM THIRD TO FIRST IT WILL FORM A RIGHT TRIANGLE. THE LEGS ARE 60 TO 2ND POWER + 60 TO THE 2ND POWER. THE HYPOTENUSE IS WHAT I DON'T KNOW TO FIGURE OUT.
60 sqrt 2
hypotenuse = sqrt (60^2+60^2)
= sqrt (2 * 60^2)
= 60 sqrt 2 = 84.85
To find the length of the hypotenuse in a right triangle with legs of 60 ft each, you can use the Pythagorean theorem. According to the theorem, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs.
So, in this case, the length of one leg is 60 ft, and the length of the other leg is also 60 ft. Therefore, the equation is:
Hypotenuse^2 = 60^2 + 60^2
Simplifying this equation would give you:
Hypotenuse^2 = 3600 + 3600
Hypotenuse^2 = 7200
To find the length of the hypotenuse, you need to take the square root of both sides of the equation:
√(Hypotenuse^2) = √7200
Hypotenuse ≈ 84.85 ft
Therefore, the distance from third base to first base is approximately 84.85 ft when rounded to the nearest hundredth.