Can you please review to see if I am on the right track with this problem:

The length of a rectangle is 2 centimeters less than two times the width of the rectangle. If the perimeter of the rectangle is 98 centimeters, what is the length of the rectangle? Write a system of equation to solve.

L = 2x-2
2x-2 =98
2x = 100
x = 50 (length)

P = 2L + 2W = 98
2 (50) + 2w = 98
100 + 2w = 98
2w = -2
w = -1

Is this correct?

How could the width be a negative number?

98 = 2(2W - 2) + 2W

98 = 6W - 4

102 = 6W

17 = W

To solve this problem, we first start by defining the variables. Let's use L for the length of the rectangle and W for the width.

According to the problem statement, the length of the rectangle is 2 centimeters less than two times the width. So, we can write the equation for the length as: L = 2W - 2.

Next, we need to consider the perimeter of the rectangle. The perimeter is the sum of all four sides, which in this case is equal to 98 centimeters. The formula for the perimeter of a rectangle is: P = 2L + 2W.

Now, to solve the problem, we need to create a system of equations by combining the given information.

1) From the length equation: L = 2W - 2
2) From the perimeter equation: 2L + 2W = 98

Now, let's solve this system of equations using substitution or elimination.

Substituting L in the perimeter equation, we have:
2(2W - 2) + 2W = 98
4W - 4 + 2W = 98
6W - 4 = 98
6W = 102
W = 17

Now, substitute the value of W back into the length equation:
L = 2(17) - 2
L = 34 - 2
L = 32

So, the length of the rectangle is 32 centimeters, not 50 as you mentioned.

It seems there was a mistake in your calculations. You accidentally mixed up the equations. Please double-check your work when substituting values and performing calculations to avoid errors.