What is equation between ethanethiol and methoxide ion?

MeONa + EtSH will give us products MeOH + EtSNa as MeONa is a base and ethanthiol is an acid will give rise to an acid-base reaction.

The reaction between ethanethiol (C2H6S) and methoxide ion (CH3O-) can be represented by the following equation:

C2H6S + CH3O- -> C2H5OCH3 + HS-

In this reaction, the ethanethiol reacts with the methoxide ion to form methyl ethyl ether (C2H5OCH3) and hydrogen sulfide (HS-).

To determine the equation between ethanethiol (C2H5SH) and methoxide ion (CH3O-), we need to consider their chemical properties and the reaction conditions.

Ethanethiol is a thiol (also known as a mercaptan) with the chemical formula C2H5SH. Methoxide ion is an alkoxide with the chemical formula CH3O-, which is derived from methanol (CH3OH) by losing a hydrogen ion (H+).

Thiols can undergo nucleophilic substitution reactions, where the thiol reacts with other electrophilic species. In this case, the methoxide ion acts as the nucleophile, attacking the sulfur atom in ethanethiol.

The reaction equation between ethanethiol and methoxide ion can therefore be written as:

C2H5SH + CH3O- → C2H5SCH3 + OH-

In this reaction, the methoxide ion replaces the hydrogen atom on the sulfur atom of ethanethiol, forming a new compound called ethyl methyl sulfide (C2H5SCH3). Meanwhile, the hydroxide ion (OH-) is formed as a byproduct.

It's important to note that the reaction conditions, such as temperature and solvent, can influence the reaction rate and outcome. Additionally, this equation represents a simplified version of the reaction, and other side reactions or intermediates may be involved, depending on the specific conditions.