Draw and repeat unit for a reaction product of glycol: HO-CH2-CH2-CH2-CH2-OH with the following carboxylic acid:
HO-C-CH2-CH2-C-OH
= =
O O
The O's are supposed to be under both the C's
To determine the product of the reaction between glycol (HO-CH2-CH2-CH2-CH2-OH) and the given carboxylic acid (HO-C-CH2-CH2-C-OH), the first step is to identify the functional groups involved.
In glycol, the functional group is the hydroxyl (-OH) group attached to the carbon chain. In the carboxylic acid, the functional groups are the hydroxyl (-OH) group and the carbonyl (C=O) group attached to the carbon chain.
The reaction between a hydroxyl group and a carboxylic acid typically forms an ester. In this case, the reaction would result in the formation of an ester by replacing the hydroxyl group (-OH) of the glycol with the carbonyl (C=O) group of the carboxylic acid.
To draw the repeat unit of the reaction product, we will combine the two molecules by connecting the carbon atom of the hydroxyl group in the glycol to the oxygen atom of the carbonyl group in the carboxylic acid. The resulting structure will have one oxygen atom serving as the bridge between the two carbon chains.
Here is the drawn and repeated unit of the reaction product:
HO-C-CH2-CH2-C-O-CH2-CH2-CH2-CH2-OH
= =
O O
In this structure, the carbon atoms are represented by the letter C, and the oxygen atoms are represented by the letter O. The '-' symbol indicates a single bond between the atoms.
It's important to note that the reaction may produce more than one unit, so the structure shown here represents the repeat unit and not the entire product.