Write the ionic equation for dissolution and the Ksp expression for PbC12.

The dissolution of lead(II) chloride (PbCl2) in water can be represented by the following ionic equation:

PbCl2(s) ⟶ Pb2+(aq) + 2Cl-(aq)

In this equation, the lead(II) chloride solid dissociates into lead(II) ions (Pb2+) and chloride ions (Cl-) in the aqueous solution.

The solubility product constant (Ksp) expression for PbCl2 can be written as:

Ksp = [Pb2+][Cl-]^2

In this expression, [Pb2+] represents the concentration of lead(II) ions and [Cl-] represents the concentration of chloride ions. The coefficients from the balanced chemical equation are used as the exponents in the Ksp expression.

To write the ionic equation for the dissolution of PbCl2 and the Ksp expression, we need to understand the chemical formula of PbCl2 and its behavior in water.

The chemical formula for lead(II) chloride is PbCl2. In water, it dissociates into its constituent ions, lead(II) cations (Pb2+) and chloride anions (Cl-).

The ionic equation for the dissolution of PbCl2 can be written as follows:

PbCl2(s) --> Pb2+(aq) + 2Cl-(aq)

This equation represents the solid lead(II) chloride dissociating into aqueous lead(II) cations and chloride anions.

Now, let's proceed to the Ksp expression for PbCl2. Ksp stands for the solubility product constant, which indicates the extent of dissolution of a sparingly soluble salt in water.

The solubility product constant expression for PbCl2 is given as follows:

Ksp = [Pb2+][Cl-]^2

In this expression, [Pb2+] represents the concentration of lead(II) cations, and [Cl-] represents the concentration of chloride anions in solution. The exponent 2 indicates that the stoichiometric coefficient of chloride in the balanced equation is 2.

Hence, the ionic equation for the dissolution of PbCl2 is PbCl2(s) --> Pb2+(aq) + 2Cl-(aq), and the Ksp expression for PbCl2 is Ksp = [Pb2+][Cl-]^2.