25 ml of 3M hno3 are mixed with 75ml of 4.0M HNO3 if volumes are additive then find molarity
you had .025*3 + .075*4 total moles put in a total volume of .100 dm^3.
molarity=totalmoles/totalvolume
To find the molarity of the resulting solution, we need to calculate the total moles of HNO3 and the total volume of the solution.
First, let's calculate the moles of HNO3 in each solution. We know the volume and molarity of each solution, so we can use the formula:
moles = volume (in liters) x molarity
For the first solution:
moles1 = 25 ml x (3 mol/L) = 0.075 mol
For the second solution:
moles2 = 75 ml x (4 mol/L) = 0.3 mol
Now, let's calculate the total moles of HNO3 by adding moles1 and moles2:
total moles = moles1 + moles2 = 0.075 mol + 0.3 mol = 0.375 mol
Next, we need to calculate the total volume of the resulting solution. Since the volumes are additive, we can simply add the volumes of the two solutions:
total volume = 25 ml + 75 ml = 100 ml
Finally, we can calculate the molarity of the resulting solution using the formula:
molarity = total moles / total volume (in liters)
To convert the total volume from milliliters to liters, divide by 1000:
total volume = 100 ml / 1000 = 0.1 L
Now, we can calculate the molarity:
molarity = 0.375 mol / 0.1 L = 3.75 M
Therefore, the molarity of the resulting solution is 3.75 M.