A 33.1 kg crate rests on a horizontal floor, and a 69.0 kg person is standing on the crate. Determine the magnitude of the normal force that the floor exerts on the crate.

9.81(33.1+69.0)

To determine the magnitude of the normal force that the floor exerts on the crate, we need to consider the forces acting on the crate.

1. Gravitational force (weight):
The crate and the person have masses of 33.1 kg and 69.0 kg, respectively. The acceleration due to gravity is approximately 9.8 m/s^2. The gravitational force acting on the crate and the person is given by:
Fg = (m1 + m2) * g

2. Normal force:
The normal force is the force exerted by a surface to support the weight of an object resting on it. When an object is placed on a horizontal surface, the normal force is equal in magnitude and opposite in direction to the gravitational force acting on the object.

So, the magnitude of the normal force is equal to the weight of the crate and the person, which is given by:
Fn = Fg

Substituting the values into the equation:
Fn = (m1 + m2) * g
= (33.1 kg + 69.0 kg) * 9.8 m/s^2

Calculate the product, and we get the magnitude of the normal force exerted by the floor on the crate.