Find f^-1 (1) and (f^-1)' (1) f^-1 (1) = 0 (f^-1)' (1) = 1/3 These are the answers given, but I also don't understand how my teacher got these.
interchange x = cos y + 3 y if y = 0, x = 1 + 0 x' = -sin y + 3 but y = 0 at x = 1 dx/dy = 3 dy/dx = 1/3
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