The high temperatures in Jacksonville, Florida for July 1 – July 15 are shown below.
80, 73, 72, 76, 84, 86, 82, 73, 81, 84, 78, 85, 87, 84, 70
Identify the following, only using numbers.
The median is
.
The minimum is
.
The maximum is
.
The lower quartile is
.
The upper quartile is
.
Evidently you don't know what a median is.
Study this page for information about medians and quartiles.
http://www.mathsisfun.com/data/quartiles.html
The median is 73
To identify the different values in the given data, you can follow these steps:
Step 1: Organize the data in ascending order:
70, 72, 73, 73, 76, 78, 80, 81, 82, 84, 84, 84, 85, 86, 87
Step 2: Find the median:
The median is the middle value of the data set, so in this case, it would be the 8th value, which is 81.
Step 3: Find the minimum:
The minimum is the smallest value in the data set, so in this case, it is 70.
Step 4: Find the maximum:
The maximum is the largest value in the data set, so in this case, it is 87.
Step 5: Find the lower quartile:
The lower quartile is the median of the lower half of the data. To find it, you need to find the median of the values below the overall median. In this case, you have 7 values below the median (70, 72, 73, 73, 76, 78, 80), so the lower quartile would be the median of these values. The 4th value would be the lower quartile, which is 73.
Step 6: Find the upper quartile:
The upper quartile is the median of the upper half of the data. To find it, you need to find the median of the values above the overall median. In this case, you have 7 values above the median (82, 84, 84, 85, 86, 87), so the upper quartile would be the median of these values. The 4th value would be the upper quartile, which is 85.
Therefore, the numerical values you asked for are:
The median is 81.
The minimum is 70.
The maximum is 87.
The lower quartile is 73.
The upper quartile is 85.