How do I find the zeros?
y=h^3+6h^2+5h-180
ht tp: //w ww. 17 28. org/ cub ic2. h tm
*remove the spaces in between.
I hope this will help you. It explains the actual process of factoring cubic equations.
http://www.wolframalpha.com/widgets/view.jsp?id=3f4366aeb9c157cf9a30c90693eafc55
They mean a,b,c,d by the way
+
and complex pair -5 +/- 2 i sqrt 5
To find the zeros of the equation y = h^3 + 6h^2 + 5h - 180, you will need to solve for h when y is equal to zero. This means you have to find the values of h that make the equation equal to zero.
Here's how you can find the zeros step by step:
1. Set y equal to zero: 0 = h^3 + 6h^2 + 5h - 180.
2. To make this equation easier to solve, you may need to factor or use polynomial long division if possible. However, in this case, factoring or using simple methods may not be straightforward. So, we will use an alternative approach.
3. Start by guessing a value for h. This value can be any number, but it could be helpful to start with small integers or fractions.
4. Substitute this guessed value of h into the equation and see if it produces zero. If it does, then this guessed value is a zero of the equation. If it doesn't, you will need to try with another guessed value.
5. Repeat step 4 until you find a value of h that makes the equation equal to zero. This value of h will be one of the zeros.
6. Once you find one zero using step 4 and 5, divide the original equation by the binomial factor (h - zero) to obtain a quadratic equation.
7. Solve this quadratic equation to find the remaining zeros if there are any. You can use factoring, completing the square, or the quadratic formula to solve this equation.
8. Repeat steps 6 and 7 if necessary until you have found all the zeros of the equation.
By following these steps, you should be able to find the zeros of the equation y = h^3 + 6h^2 + 5h - 180.