F(x)= 3/2x +b
In the function above, b is a constant. If f(6)=7, what is the value of f(-2) ?
f(6)=9+b assuming you meant (3/2)x
b=7-9=-2
f(-2)=(3/2)(-2)-2=-3-2=-5
Well, if f(6) equals 7, then we can substitute x with 6 and find the value of b. So let me do some math circus tricks here.
f(6) is given as 7, so we have:
7 = (3/2)(6) + b
Now let's perform the calculations:
7 = 9 + b
Subtracting 9 from both sides, we get:
-2 = b
So, the value of b is -2.
Now, let's use our newfound knowledge and plug in -2 for b in the original function to find f(-2):
f(x) = (3/2)x + b
f(-2) = (3/2)(-2) + (-2)
Using our clown-like math skills again:
f(-2) = -3 + (-2)
f(-2) = -5
Ta-da! The value of f(-2) is -5!
To find the value of f(-2), we need to substitute x = -2 into the function and solve for f(-2).
Given: f(x) = (3/2)x + b
We know that f(6) = 7. Substituting x = 6 and f(x) = 7 into the function gives us:
7 = (3/2)(6) + b
Now we can solve for b:
7 = 9 + b
b = 7 - 9
b = -2
Now that we have the value of b, we can substitute x = -2 into the original function:
f(-2) = (3/2)(-2) + (-2)
f(-2) = -3 + (-2)
f(-2) = -5
Therefore, the value of f(-2) is -5.
To find the value of f(-2) in the given function, we need to substitute -2 into the function and solve for f(-2).
Given:
f(x) = (3/2)x + b
First, let's use the fact that f(6) = 7 to find the value of the constant b:
f(6) = (3/2)(6) + b (Substituting x = 6 into the function)
7 = 9 + b (Simplifying)
b = 7 - 9 (Subtracting 9 from both sides)
b = -2 (Evaluating)
Now, we have the value of b as -2.
Next, substitute x = -2 into the function to find f(-2):
f(-2) = (3/2)(-2) + (-2) (Substituting x = -2 and b = -2 into the function)
f(-2) = -3 + (-2) (Simplifying)
f(-2) = -5 (Adding -3 and -2)
Therefore, the value of f(-2) is -5.