The sum of two nos is 40, the smaller no is 6 less than the larger no, Find the nos
4 and 10
clearly 4+10 ≠ 40
(though, 4*10=40)
x-6 + x = 40
x = 17
17+23 = 40
To solve this problem, let's call the larger number "x" and the smaller number "y".
According to the given information, the sum of the two numbers is 40: x + y = 40.
It is also given that the smaller number is 6 less than the larger number: y = x - 6.
To find the values of x and y, we can substitute the value of y from the second equation into the first equation:
x + (x - 6) = 40.
Now we need to solve this equation for x.
Combining like terms, we get: 2x - 6 = 40.
Adding 6 to both sides of the equation: 2x = 46.
Dividing both sides by 2, we find: x = 23.
Now we can substitute the value of x back into the second equation to find y:
y = 23 - 6.
Simplifying, we get: y = 17.
So, the two numbers are 23 and 17.