Carbohydrates (such as C6H12O6) undergo combustion with oxygen to produce carbon dioxide and water. Living things use this reaction (a process called respiration) to produce energy.
Determine the mass of carbohydrates consumed for every 0.300 mol of oxygen gas consumed during respiration.
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To determine the mass of carbohydrates consumed for every 0.300 mol of oxygen gas consumed during respiration, we need to use the balanced chemical equation for the combustion of carbohydrates with oxygen.
The balanced equation can be written as:
C6H12O6 + 6O2 → 6CO2 + 6H2O
From the equation, we can see that 1 mole of C6H12O6 reacts with 6 moles of O2 to produce 6 moles of CO2 and 6 moles of H2O.
To calculate the mass of carbohydrates, we need to know the molar mass of C6H12O6. The molar mass of glucose (C6H12O6) is approximately 180.16 g/mol.
Now we can set up the following proportion:
(1 mol C6H12O6) / (6 mol O2) = (x g C6H12O6) / (0.300 mol O2)
To solve for the mass of carbohydrates (x), we can rearrange the proportion:
x = (1 mol C6H12O6 / 6 mol O2) * (0.300 mol O2) * (180.16 g C6H12O6 / 1 mol C6H12O6)
x = (0.050 mol C6H12O6) * (180.16 g C6H12O6 / 1 mol C6H12O6)
x = 9.008 g
Therefore, the mass of carbohydrates consumed for every 0.300 mol of oxygen gas consumed during respiration is approximately 9.008 grams.