A tree broke due to storm at a point but did not get separate . its tops touched the ground at a distance of 10 m from its base if the height of the point from the ground at which the tree was broken is 12\25 of the total height of the tree find its height
Hum ko samajh main nahi aaya
To solve the problem, let's denote the total height of the tree as 'H'.
We are given that the tops of the broken tree touched the ground at a distance of 10 m from its base. This means that the remaining part of the tree, after it broke, has a height of H - 10 m.
We are also given that the height of the point where the tree broke from the ground is 12/25 of the total height of the tree. Therefore, the height of the broken part is (12/25)H.
Now, since the broken part and the remaining part of the tree together make up the total height (H), we can write the equation:
(H - 10) + (12/25)H = H
Simplifying this equation, we get:
25(H - 10) + 12H = 25H
25H - 250 + 12H = 25H
37H - 250 = 25H
37H - 25H = 250
12H = 250
H = 250 / 12
H = 20.83
Therefore, the height of the tree is approximately 20.83 meters.
Humko samajh mai nhi aaya
If the tree's height is x meters, the broken tree forms a right triangle with sides 12/25 x and 10. The hypotenuse is 13/25 x.
10^2 + (.48x)^2 = (.52x)^2
Now just solve for x.