A student was experimentally checking the stoichiometry of a reaction. The student correctly predicted that the reaction should produce 1.82 g of al2(so4)3(s). When the student dried and weighed the al2(so4)3(s) produced, its mass was 1.94 g. The percent difference of the experiment was?
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The 1.82 is 100%. That is theoretical yield (TY).
The 1.94 is actual yield (AY)
% yield = (AY/TY)*100 = ?
You can take the difference.
To find the percent difference between the predicted and actual masses of the \(Al_2(SO_4)_3(s)\), you need to follow these steps:
1. Calculate the absolute difference between the predicted and actual masses:
Absolute difference = Actual mass - Predicted mass
\(Absolute difference = 1.94 g - 1.82 g = 0.12 g\)
2. Calculate the percent difference using the formula:
Percent Difference = (Absolute difference / Predicted mass) * 100
\(Percent Difference = (0.12 g / 1.82 g) * 100\)
3. Calculate the value of the expression in parentheses:
\(Value = 0.12 g / 1.82 g = 0.0659\)
4. Multiply the value by 100 to get the percent difference:
Percent Difference = 0.0659 * 100 = 6.59%
Therefore, the percent difference between the predicted and actual masses of \(Al_2(SO_4)_3(s)\) is approximately 6.59%.