The sum of three numbers is 82. One of the numbers is 9 more than one of the others. Represent the numbers in terms of one variable.
So this is what I got:
(b+9)+b+c=82
that means that
c= 82-((b+9)+b)
putting it all together we have
(b+9)+b+82-((b+9)+b)= 82
first number ---- x
second number --- x+9
third number ----- 82 - x - x - 9
= 72 -2x
all three numbers are expressed in terms of one variable:
x , x+9, and 72-2x
To represent the numbers in terms of one variable, let's assume the variable as 'x'.
Let's assign 'x' to the smallest number among the three.
Since one of the numbers is 9 more than one of the others, we can represent the second number as 'x + 9'.
Similarly, the third number can be represented as 'x + x + 9' (as the sum of all three numbers is 82).
So, the representation of three numbers in terms of one variable is:
x, x + 9, and 2x + 9.