-2x^2+10x+3=0
What is the factored version of this??
It does not factor over the rationals, since the discriminant
b^2-4ac = 100+24 = 124
is not a perfect square. Use the quadratic formula to find the roots, or maybe there's a typo.
When I did it I got x=5+-[19] over by 2
interesting, since 124 = 4*31
Where did you get the 19?
"over by"? Try just "over"
Better yet, use real math
(5+-[31])/2
Though I have never seen [] used to denote square root before.
Ya whatever I got it right in class so u were no help but thank you for trying
To find the factored version of the given quadratic equation, we need to use a method called factoring. Here's how you can do it step by step:
Step 1: Begin by multiplying the coefficient of the x^2 term (-2) by the constant term (3). In this case, it gives you -6.
Step 2: Now, think of two integers whose product is -6 and whose sum is the coefficient of the x-term (10). In this case, the integers are -2 and -3 because -2 * -3 = 6 and -2 + (-3) = -5.
Step 3: Rewrite the middle term (10x) using the two integers from step 2. Replace 10x with -2x and -3x, which gives you:
-2x^2 - 2x - 3x + 3 = 0
Step 4: Group the terms together so that you can factor by grouping. Rearrange the equation like this:
(-2x^2 - 2x) + (-3x + 3) = 0
Step 5: Factor out the greatest common factor (GCF) from the terms in each group. The GCF of the first group is -2x, and the GCF of the second group is -3.
-2x(x + 1) - 3(x - 1) = 0
Step 6: Notice that you have a common binomial factor of (x + 1) in both terms. Factor it out:
(x + 1)(-2x - 3) = 0
Therefore, the factored version of the equation -2x^2 + 10x + 3 = 0 is (x + 1)(-2x - 3) = 0.