An empty SG bottle weights 25 g.When filled with water completely it weights 55 g and with alcohol it weights 48 g. Find the RD of alcohol
A numerical
See previous post.
To find the relative density (RD) of alcohol, we need to compare its density to that of water.
First, let's calculate the density of water:
Density = Mass / Volume
Given that an empty SG (Specific Gravity) bottle weighs 25 g and when filled with water completely it weighs 55 g, we can calculate the mass of the water:
Mass of water = Weight of filled bottle - Weight of empty bottle = 55 g - 25 g = 30 g
Now, let's calculate the volume of water:
Density of water = Mass of water / Volume of water
Rearranging the formula, we get:
Volume of water = Mass of water / Density of water = 30 g / Density of water
Since the density of water is known to be 1 g/cm^3, we substitute this value into the equation:
Volume of water = 30 g / 1 g/cm^3 = 30 cm^3
Now, let's find the RD of alcohol:
RD = Density of alcohol / Density of water
To find the density of alcohol, we can use the information given:
When the SG bottle is filled completely with alcohol, it weighs 48 g.
Therefore, the mass of the alcohol is:
Mass of alcohol = Weight of filled bottle - Weight of empty bottle = 48 g - 25 g = 23 g
Since the volume of the bottle remains constant, the volume of alcohol will be the same as the volume of water, which is 30 cm^3.
Now, we can calculate the density of alcohol:
Density of alcohol = Mass of alcohol / Volume of alcohol = 23 g / 30 cm^3
Finally, we can substitute the densities into the RD formula:
RD = (23 g / 30 cm^3) / 1 g/cm^3
Simplifying the expression, we get:
RD = 23 / 30
Therefore, the RD of alcohol is approximately 0.767.