Mrs. Jones and Mr. Graham had the same amount of money at first. After Mrs. Jones bought a computer that cost $2,055, she had 1/4 as much money as Mr. Graham. How much money did Mr. Graham have?
I know that x = y in equation 1. I know that x-2055 = .25G for another. I'm stuck from there.
you second equation is
x-2055 = .25y , what's with the G ?
but y = x
x-2055 = .25x
.75x = 2055
x = 2740
To solve this problem, we can set up two equations based on the given information.
Let's assume that Mrs. Jones and Mr. Graham initially had the same amount of money, represented by the variables x and y respectively.
From the problem, we know that after Mrs. Jones bought a computer for $2,055, she had 1/4 the amount of money Mr. Graham had. So we can write the first equation:
x - 2055 = 1/4(y)
Now, since we are asked to find out how much money Mr. Graham had, we need to eliminate x from the equation. We can use the fact that initially x and y were the same, so we can substitute x with y in the equation:
y - 2055 = 1/4(y)
Now, let's solve this equation step by step:
Multiply both sides by 4 to get rid of the fraction:
4(y - 2055) = y
Distribute 4 on the left side:
4y - 8220 = y
Subtract y from both sides:
3y - 8220 = 0
Add 8220 to both sides:
3y = 8220
Divide both sides by 3:
y = 8220 / 3
y = 2,740
Therefore, Mr. Graham initially had $2,740.
To double-check the answer, we can substitute y back into the first equation:
x - 2055 = 1/4(y)
x - 2055 = 1/4(2740)
x - 2055 = 685
If we solve for x, we find:
x = 2055 + 685 = 2740
So, our initial assumption is correct, x = y, and both Mrs. Jones and Mr. Graham initially had $2,740.