Two chemicals,A and B are combined in the ratio 5:11 by volume to form another solution X. A second solution Y is formed by combining chemicals, A,B and C in the ratio 2:3:15 by volume.
Find the volume of chemical A in 400 litres of solution X and chemicals C in 400 litres of solution Y.
A : B = 5:11 = 10 : 22 = ... = 10x : 22x
A : B : C = 2:3:15 = 10:15:75 = ... = 10x:15x:75x
in solution X we have 10x/(22x) of A
so amount of A in 400 L ofX is (10/22)(400) = appr 181.8 L
in solution Y amount of C in 400 L
= 75x/(100x)(400) = 300 L
To find the volume of chemical A in 400 litres of solution X, we first need to calculate the total volume of the solution.
The total volume of the solution X is the sum of the volumes of chemicals A and B in the given ratio.
Let's assume the volume of chemical A is 5x litres and the volume of chemical B is 11x litres.
Therefore, the total volume of solution X is 5x + 11x = 16x liters.
We are given that the total volume of solution X is 400 litres.
So, 16x = 400.
Solving this equation, we find x = 400 / 16 = 25.
Now, we can find the volume of chemical A in 400 liters of solution X.
The volume of chemical A = 5x = 5 * 25 = 125 liters.
Therefore, the volume of chemical A in 400 liters of solution X is 125 liters.
Next, let's find the volume of chemical C in 400 liters of solution Y.
In solution Y, the ratio of the volumes of chemicals A, B, and C is given as 2:3:15.
Let's assume the volume of chemical A is 2x liters, the volume of chemical B is 3x liters, and the volume of chemical C is 15x liters.
The total volume of solution Y is the sum of the volumes of chemicals A, B, and C.
So, the total volume of solution Y = 2x + 3x + 15x = 20x liters.
Given that the total volume of solution Y is 400 liters, we can set up the following equation: 20x = 400.
Solving for x, we find x = 400 / 20 = 20.
Now, we can find the volume of chemical C in 400 liters of solution Y.
The volume of chemical C = 15x = 15 * 20 = 300 liters.
Therefore, the volume of chemical C in 400 liters of solution Y is 300 liters.
To find the volume of chemical A in 400 liters of solution X, we need to determine the ratio in which chemicals A and B are combined.
Given that the ratio of A and B in solution X is 5:11, we can first calculate the total parts of the ratio:
Total parts = 5 + 11 = 16
To find the volume of chemical A in 400 liters of solution X, we need to divide the total parts by the volume of the solution and then multiply it by the volume of chemical A:
Volume of A in solution X = (5/16) * 400 = 125 liters
Therefore, the volume of chemical A in 400 liters of solution X is 125 liters.
Similarly, to find the volume of chemical C in 400 liters of solution Y, we need to determine the ratio in which chemicals A, B, and C are combined.
Given that the ratio of A, B, and C in solution Y is 2:3:15, we can calculate the total parts of the ratio:
Total parts = 2 + 3 + 15 = 20
To find the volume of chemical C in 400 liters of solution Y, we need to divide the total parts by the volume of the solution and then multiply it by the volume of chemical C:
Volume of C in solution Y = (15/20) * 400 = 300 liters
Therefore, the volume of chemical C in 400 liters of solution Y is 300 liters.