4b/2 + 3 = 11 + b
i know the answer is b=8 but i want to know how
4b/2 + 3 = 11 + b
2b + 3 = 11 + b, since 4/2 = 2
2b - b = 11-3
b = 8
or
4b/2 + 3 = 11 + b
multiply every term by 2
4b + 6 = 22 + 2b
4b - 2b = 22 - 6
2b = 16
divide both sides by 2
b = 8
To solve the given equation 4b/2 + 3 = 11 + b, you need to isolate the variable "b" on one side of the equation. Here's how to do it step by step:
1. Start by simplifying both sides of the equation. On the left side, the 4b/2 can be simplified to just 2b. So the equation becomes 2b + 3 = 11 + b.
2. Next, get rid of the variable terms on one side of the equation. You can do this by subtracting "b" from both sides. This gives you 2b - b + 3 = 11.
3. Simplify the equation further. On the left side, 2b - b simplifies to just b. So the equation becomes b + 3 = 11.
4. Now, subtract 3 from both sides of the equation to eliminate the constant term on the left side. This gives you b + 3 - 3 = 11 - 3.
5. Simplify further to get b = 8.
Therefore, the solution to the equation 4b/2 + 3 = 11 + b is b = 8.