Separate 51 into 2 parts so the second part is 3 more than twice as large as the first part
x + 2x+3 = 51
To separate 51 into two parts where the second part is 3 more than twice as large as the first part, we can use variables to represent the parts.
Let's say the first part is represented by x. According to the given condition, the second part is 3 more than twice as large as the first part. This can be expressed as 2x + 3.
Since we know that the sum of the two parts is 51, we can write an equation:
x + (2x + 3) = 51
Now, let's solve the equation to find the values of x and 2x + 3.
Combining like terms, we have:
3x + 3 = 51
Subtracting 3 from both sides:
3x = 48
Dividing both sides by 3:
x = 16
Now we can find the value of the second part:
2x + 3 = 2(16) + 3 = 35
So, the first part is 16 and the second part is 35, where the second part is indeed 3 more than twice as large as the first part.